Maths question

Let’s assume I have a (big) bucket of 100l capacity.

I put into it 50l of cleaning solution that is diluted to 2%.

I then fill it by adding 50l of water.

The eventual solution, it’s equivalent to 1%, right?

I just want to check that’s how it works (which is my understanding) and not something seemingly gonzo like the Monty Hall problem.

Close enough if you’re not titrating with it.

It’s certainly close – very close. But things in solution cause (small) changes in the volume of solvents (in this case water) that aren’t exactly as you might expect from the volume of the stuff you’ve added. Once something’s already down to 2% any further effect on the solvent’s density is likely to very minor indeed.

Thanks.

On Fridays we fill up a huge basin with a cleaning solution, and to determine a good amount (as it’s been a bit haphazard), I am to make up small doses in a pitcher and test them.
The reason is that “the tap” that gives the premixed solution does so incredibly slowly, so if, say, half and half with water works then that would be a benefit to us in terms of time, so long as the actual concentration can be determined and it reads ph13 (like it should).

I thought cutting it with an equal amount of water would halve the concentration, but wanted to check.

So, thanks again for the quick responses.

If the premix was more concentrated, then you have to watch out for order! Acid/Alkali into water, not the other way round.

Indeed, but I can’t think of anything where 2% is concentrated enough for that to matter.

Isn’t that about the percentage of Americans fighting against the English and the Hessians-on-hire way back when?